# JEE Mains Admit Card 2021- Most Anticipated Questions for JEE Mains March Exam.

## JEE Mains March Admit Card & other Important Information.

Congratulations to all the students who scored well in JEE Mains February Session. NTA has released the Admit Card for JEE Mains 2021 March exams on its official website. Students can use any of the three links provided by NTA to download the Admit Card.

JEE Mains March Time Table

JEE Mains March Admit Card | Available from 11th,March. |

JEE Mains March Exam Dates | March 16th- March 18th |

*NTA has changed the dates from the original schedule of March 15th- March 18th.

## How to Download JEE Mains March Admit Card?

Students need their JEE Application number & date of birth to download the admit card for their exam. Visit jeemain.nta.nic.in & enter the above details to download the pdf of the admit card. There are 331 Exam centers across India for students to write the exam.

### Documents to Carry to Exam Centers?

Along with the clear printout of the Admit card students are required to carry a valid original photo ID. Students should take note that photocopies of the ID will not be accepted at the center.

In case of any issues in downloading the Admit card students are advised to directly contact NTA at jeemain-nta@gov.in

### Important Instructions for JEE Mains 2021

Watches are strictly prohibited in the exam center.

Students are not allowed to bring Pen/Pencils

Everyone should write their roll number on the rough sheets provided.

Diabetics are allowed to carry some sweetened food & transparent bottles.Packaged food is strictly prohibited.

## Reattempt JEE Mains February Exams- Complete Solutions

## What are the most Anticipated Questions for JEE Mains 2021 March & April Sessions?

Rizee’s anticipated Questions are based on JEE Mains Previous Year Question papers analysis & based on the trend of questions asked in JEE Mains February Question Papers. Expert faculty at Rizee has successfully predicted more than 50% of Chapters asked in JEE Mains February Question Papers.

Mathematics Important Questions FREE PDF

Physics Important Questions FREE PDF

Chemistry Important Questions FREE PDF

**Most Anticipated Questions for JEE Main Mathematics **

**Q1. The value of ****(21**_{C}_{1}**−10**_{C}_{1}**) + (21**_{C}_{2}**−10**_{C}_{2}**) − (21**_{C}_{3}**−10**_{C}_{3}**) +(21**_{C}_{4}**−10**_{C}_{4}**) + ⋯ + (21**_{C}_{10}**−10**_{C}_{10}**) ****is **

_{C}

_{1}

_{C}

_{1}

_{C}

_{2}

_{C}

_{2}

_{C}

_{3}

_{C}

_{3}

_{C}

_{4}

_{C}

_{4}

_{C}

_{10}

_{C}

_{10}

**(A) **2^{20 }− 2^{10 } **(B) **2^{21 }− 2^{11}

**(C) **2^{21 }− 2^{10 } **(D) **2^{20 }− 2^{9}

**Explanation : ****(A) **

(21_{C}_{1}+21_{C}_{2 }+ 21_{C}_{3 }− 21_{C}_{4 }+ ⋯ + 21_{C}_{10}) − (10_{C}_{1 }+ 10_{C}_{2 }+ 10_{C}_{3 }+ ⋯ + 10_{C}_{10}) =^{1}_{2}2^{21 }− 2 − 2^{10 }− 1 = 2^{20 }− 2 − 2^{10 }− 1 = 2^{20 }− 2^{10}

**Q2. Matrix A such that ****A**^{2}**= 2A –I, where I is the identity matrix, Then for n****≥****2, ****A**^{n}**is equal to?**

^{2}

^{n}

**(A) **2^{n;1}A − n − 1 I **(B) **2^{n;1}A − I

**(C) **nA − n − 1 I **(D) **nA − I

**Explanation : ****(C) **

Given, A^{2 }= 2A − I

Now, A^{3 }= A(A^{2})

= A(2A − I)

= 2A^{2 }− A

= 2 2A − I − A = 3A − 2I

A^{4 }= A(A^{3})

= A(3A − 2I)

= 3A^{2 }− 2A

= 3 2A − I − 2A = 4A − 3I

Following this, we can say A^{n }= nA − n − I I.

**Chapter Name : **MATRICES **Topic Name : **TYPES AND ALGEBRA OF MATRICES,TRANSPOSE AND SPECIAL TYPES OF MATRICES (APPLICATION)

**Q3. If the straight line x – 2y + 1 = 0 intersects the circle ****x**^{2 }**+ y**^{2 }**= 25 ****in points P and Q then the coordinates of the point of intersection tangents drawn at P and Q to the circle ****x**^{2 }**+ y**^{2 }**= 25 ****are?**

^{2 }

^{2 }

^{2 }

^{2 }

**(A) **(25,50) **(B) **(-25,-50)

**(C) **(-25,50) **(D) **(25,-50)

**Explanation : ****(C) **

Let R(h,k) be the point of intersection of tangents drawn at P and Q to the given circle. Then, PQ is the chord of contact of tangents drawn from R to x^{2 }+ y^{2 }= 25. So its equation is hx + ky – 25 = 0 …..(i)

It is given that the equation of PQ is

x – 2y + 1 = 0 …..(ii)

Since (i) and (ii) represent the same line

∴^{h}_{1}=^{k}_{;2}= −^{25}1

⇒ h = – 25,k = 50

Hence, the required point is (-25,50)

**Download the Free PDF of Anticipated Questions JEE Mains Mathematics**

Sample Questions & Explanations

**Most Anticipated Questions for JEE Main Physics March Exam- Download Complete PDF**

## Most Anticipated Questions JEE Mains Chemistry March Exams.

Sample Chemistry Questions & Explanations

All the best for the Students who are appearing in JEE Mains 2021 March & JEE Mains 2021 April Sessions.You can read the complete strategy to score better in upcoming sessions here.

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